SSC CPO practice question
On a 1.6 km circular track, two runners run in the same direction, starting together from the same point. The ratio of their speeds is 5:3. The faster runner's speed is 25 km/h. After how much time will they meet again for the first time?
From a SSC CPO Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (C) 9.6 minutes
Since speed ratio is 5:3 and the faster speed (5 units) = 25 km/h, one unit = 5 km/h, so the slower speed = 3 × 5 = 15 km/h. Relative speed = 25 - 15 = 10 km/h. Time to meet again = 1.6/10 hours = 0.16 hours = 9.6 minutes.
हिंदी में प्रश्न
1.6 किमी लंबे एक गोलाकार ट्रैक पर, दो धावक एक ही बिंदु से एक साथ शुरू होकर एक ही दिशा में दौड़ते हैं। उनकी चालों का अनुपात 5:3 है। तेज धावक की चाल 25 किमी/घंटा है। वे पहली बार दोबारा कब मिलेंगे?
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सही उत्तर: (C) 9.6 मिनट
चूँकि चाल का अनुपात 5:3 है और तेज चाल (5 इकाई) = 25 किमी/घंटा है, तो 1 इकाई = 5 किमी/घंटा, अतः धीमी चाल = 3 × 5 = 15 किमी/घंटा। सापेक्ष चाल = 25 - 15 = 10 किमी/घंटा। दोबारा मिलने का समय = 1.6/10 घंटे = 0.16 घंटे = 9.6 मिनट।
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