IBPS RRB Officer Scale-I Prelims practice question
Using log10 2 = 0.301 and log10 3 = 0.477, find the value of log₂12 (nearest to two decimal places).
From a IBPS RRB Officer Scale-I Prelims Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (D) 3.58
log10 12 = 2log2 + log3 = 0.602+0.477 = 1.079. log₂12 = 1.079/0.301 ≈ 3.58.
हिंदी में प्रश्न
log10 2 = 0.301 तथा log10 3 = 0.477 का उपयोग करके log₂12 का मान (दो दशमलव स्थान तक निकटतम) ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 3.58
log10 12 = 2log2 + log3 = 0.602+0.477 = 1.079. log₂12 = 1.079/0.301 ≈ 3.58.
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