SSC CHSL Tier-1 practice question
A chord of length 48 cm is drawn in a circle of radius 40 cm. Find the perpendicular distance of the chord from the centre of the circle.
From a SSC CHSL Tier-1 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (C) 32 cm
Half-chord = 48/2 = 24 cm. Radius = 40 cm. Distance from centre = sqrt(radius2 - half-chord2) = sqrt(1600 - 576) = sqrt(1024) = 32 cm. Hence, the answer is 32 cm.
हिंदी में प्रश्न
40 सेमी त्रिज्या वाले एक वृत्त में 48 सेमी लंबाई की एक जीवा खींची गई है। केंद्र से जीवा की लंबवत दूरी ज्ञात कीजिए।
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सही उत्तर: (C) 32 सेमी
जीवा का आधा भाग, केंद्र से लंबवत दूरी और त्रिज्या एक समकोण त्रिभुज बनाते हैं, जिसमें त्रिज्या कर्ण होती है। पाइथागोरस प्रमेय का उपयोग करने पर, उत्तर 32 सेमी प्राप्त होता है।
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