IBPS RRB Officer Scale-I Prelims practice question
A jeweller calculates a design difference as 5√2 − 2√5 (in grams). Using √2 = 1.414 and √5 = 2.236, find this value to 3 decimal places.
From a IBPS RRB Officer Scale-I Prelims Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (C) 2.598
5√2 = 5 × 1.414 = 7.070; 2√5 = 2 × 2.236 = 4.472. Difference = 7.070 − 4.472 = 2.598.
हिंदी में प्रश्न
एक जौहरी एक डिज़ाइन अंतर की गणना 5√2 − 2√5 (ग्राम में) के रूप में करता है। √2 = 1.414 और √5 = 2.236 का उपयोग करते हुए, यह मान 3 दशमलव स्थान तक ज्ञात करें।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) 2.598
5√2 = 5 × 1.414 = 7.070; 2√5 = 2 × 2.236 = 4.472। अंतर = 7.070 − 4.472 = 2.598।
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