IBPS RRB Officer Scale-I Prelims practice question
At the same constant speed, 3 patrol jeeps running 9 hours a day cover 1080 km in 4 days. Find the number of days needed for 6 such patrol jeeps running 6 hours a day to cover 1080 km.
From a IBPS RRB Officer Scale-I Prelims Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (A) 3 days
Using the chain (combined variation) rule: (A1 x H1 x d1)/D1 = (A2 x H2 x d2)/D2.
Per-unit rate k = D1/(A1 x H1 x d1) = 1080/(3 x 9 x 4) = 10 km per vehicle-hour.
So d2 = D2/(A2 x H2 x k) = 1080/(6 x 6 x 10) = 3 days.
Per-unit rate k = D1/(A1 x H1 x d1) = 1080/(3 x 9 x 4) = 10 km per vehicle-hour.
So d2 = D2/(A2 x H2 x k) = 1080/(6 x 6 x 10) = 3 days.
हिंदी में प्रश्न
समान स्थिर गति पर, प्रतिदिन 9 घंटे चलने वाले 3 गश्ती जीपें, 4 दिनों में 1080 किमी तय करते हैं। प्रतिदिन 6 घंटे चलने वाले 6 ऐसे गश्ती जीपें को 1080 किमी तय करने में कितने दिन लगेंगे, ज्ञात कीजिए।
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सही उत्तर: (A) 3 दिन
चेन (संयुक्त भिन्नता) नियम से: (A1 x H1 x d1)/D1 = (A2 x H2 x d2)/D2.
प्रति इकाई दर k = D1/(A1 x H1 x d1) = 1080/(3 x 9 x 4) = 10 किमी प्रति वाहन-घंटा।
अतः d2 = D2/(A2 x H2 x k) = 1080/(6 x 6 x 10) = 3 दिन।
प्रति इकाई दर k = D1/(A1 x H1 x d1) = 1080/(3 x 9 x 4) = 10 किमी प्रति वाहन-घंटा।
अतः d2 = D2/(A2 x H2 x k) = 1080/(6 x 6 x 10) = 3 दिन।
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