AP Police Constable previous year question
of 36 + [7 + {8(3 - 5) + 5(3 + 2) -1} -7] =
Asked in AP Police Constable Prelims: 2016 (06 Nov 2016) · Quantitative Aptitude
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Correct answer: (C) 32
Concept:
Follow BODMAS rule to solve this question, as per the order given below,
Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the
bracket, the BODMAS rule must be followed,</strong
Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,
Step-3-Next, the parts of the equation that contain 'Division' and 'Multiplication' are
calculated,
Step-4-Last but not least, the parts of the equation that contain 'Addition' and
'Subtraction' should be calculated.
Calculation:
2/3 of 36 + [7 + {8(3 – 5) + 5(3 + 2) – 1} – 7]
⇒ 2/3 of 36 + [7 + {8(-2) + 5(5) – 1} – 7]
⇒ 2/3 of 36 + [7 + {(-16) + 25 – 1} – 7]
⇒ 2/3 of 36 + [7 + 8 – 7]
⇒ 2/3 × 36 + 8
⇒ 24 + 8
⇒ 32
हिंदी में प्रश्न
36 యొక్క [7 + {8(3 - 5) + 5(3 + 2) -1} -7] =
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) 32
अवधारणा:
इस प्रश्न को हल करने के लिए नीचे दिए गए क्रम के अनुसार BODMAS नियम का पालन करें,
चरण-1- समीकरण के 'कोष्ठक (Brackets)' में दिए भागों को सबसे पहले हल करें, और कोष्ठक के भीतर भी BODMAS नियम का ही पालन करना चाहिए,
चरण-2- इसके बाद कोई भी 'ऑफ (Of)' या 'घातांक (Exponent)' हल करें,
चरण-3- फिर, समीकरण के उन भागों की गणना करें जिनमें 'भाग (Division)' और 'गुणा (Multiplication)' है,
चरण-4- अंत में, समीकरण के उन भागों की गणना करें जिनमें 'जोड़ (Addition)' और
'घटाव (Subtraction)' है।
गणना:
2/3 of 36 + [7 + {8(3 – 5) + 5(3 + 2) – 1} – 7]
⇒ 2/3 of 36 + [7 + {8(-2) + 5(5) – 1} – 7]
⇒ 2/3 of 36 + [7 + {(-16) + 25 – 1} – 7]
⇒ 2/3 of 36 + [7 + 8 – 7]
⇒ 2/3 × 36 + 8
⇒ 24 + 8
⇒ 32
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